[5(c+1)]=(3c-14)

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Solution for [5(c+1)]=(3c-14) equation:


Simplifying
[5(c + 1)] = (3c + -14)

Reorder the terms:
[5(1 + c)] = (3c + -14)
[(1 * 5 + c * 5)] = (3c + -14)
[(5 + 5c)] = (3c + -14)
[5 + 5c] = (3c + -14)

Remove brackets around [5 + 5c]
5 + 5c = (3c + -14)

Reorder the terms:
5 + 5c = (-14 + 3c)

Remove parenthesis around (-14 + 3c)
5 + 5c = -14 + 3c

Solving
5 + 5c = -14 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
5 + 5c + -3c = -14 + 3c + -3c

Combine like terms: 5c + -3c = 2c
5 + 2c = -14 + 3c + -3c

Combine like terms: 3c + -3c = 0
5 + 2c = -14 + 0
5 + 2c = -14

Add '-5' to each side of the equation.
5 + -5 + 2c = -14 + -5

Combine like terms: 5 + -5 = 0
0 + 2c = -14 + -5
2c = -14 + -5

Combine like terms: -14 + -5 = -19
2c = -19

Divide each side by '2'.
c = -9.5

Simplifying
c = -9.5

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